Question

In ∆ ABC and ∆PQR, in a one to one correspondence AB/QR=BC/PR = CA/PQ then. A- ∆PQR~∆ABC, B- ∆ PQR~∆CAB,C- ∆CBA~∆PQR ,D- ∆ BCA~∆ PQR ​

Answer 1

Answer:

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