In ABC and PQR , side AB=side PQ, side BC=side PR ,side AC=side QR then ----by SSS test.(As per the correspondence between vertices)
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Answer:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴A(△ABC)A(△PQR)=AB×BCPQ×QR=5×96×10=34
Step-by-step explanation:
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