Question

In ∆ABC , angle A=100°, AD bisects angle A and AD ,BC . Find angle B​

Answer 1

Step-by-step explanation:

in △ABC ,

∠BAD + ∠ADB + ∠DBA= 180∘

50∘ + 90∘ + ∠DBA= 180∘

∠DBA= 180∘ - 140 = 40∘

∴ ∠B = 40∘

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Answer 2

Answer:

this is your Answer ..........