Question

in ∆ABC, angle A=2, angle B, angle C = angle A+ 30 degree, angle A= what?​

Answer 1

Let angle A = x

Angle B = y

As mentioned in the question angle C = 3 angle B = 3y

Angle C is also given as 2(Angle A + Angle B)

= 2(x+y)

So,

3y = 2(x+y)

y = 2x

So angle C = 3y = 6x

We know that sum of all the 3 angles in a triangle = 180deg

Therefore,

Angle A+ Angle B + Angle C = 180

x+ 2x+ 6x = 180

x = 20

Hence Angle A = 20

Angle B = 40

Angle C = 120

Answer 2

Answer:

angle A=2B C=A+30 then C=2B+30 (A=2B) 180=A+B+C. then180=2b+b+2b+30 phir B=32° A=64 to C=180- (A+B) then C=180-96=84