Math, asked by alpap430, 7 months ago

In ∆ABC , angle A = 2x-10°, angle B= x+10° and angle C = 2x-20° then find the measure of each angle of ∆ ABC°.​

Answers

Answered by sharanyalanka7
16

Step-by-step explanation:

we know that sum of three angles in a triangle=180°

A+B+C=180°

2x-10°+x+10°+2x-20°=180°

5x-20°=180°

5x=200°

x=40°

A=2x-10°=2(40°)-10°=70°

B=x+10°=40°+10°=50°

C=2x-20°=2(40°)-20°=60°

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Answered by Anonymous
4

sum of all angles in a triangle is 180 degrees. there fore A+B+C=180 = 2x-10+x+10+2x-20=5x-20. 5x-20=180 5x=200 x= 40 therefore A =70 degrees. B=50 degrees. C=60 degrees

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