In ∆ABC , angle A = 2x-10°, angle B= x+10° and angle C = 2x-20° then find the measure of each angle of ∆ ABC°.
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16
Step-by-step explanation:
we know that sum of three angles in a triangle=180°
A+B+C=180°
2x-10°+x+10°+2x-20°=180°
5x-20°=180°
5x=200°
x=40°
A=2x-10°=2(40°)-10°=70°
B=x+10°=40°+10°=50°
C=2x-20°=2(40°)-20°=60°
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sum of all angles in a triangle is 180 degrees. there fore A+B+C=180 = 2x-10+x+10+2x-20=5x-20. 5x-20=180 5x=200 x= 40 therefore A =70 degrees. B=50 degrees. C=60 degrees
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