in ∆ ABC angle A=60° BC,=12 cm find the cricumradius of triangle
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Answer:
Using Pythagoras theorem,
In right angled triangle ABC,
AC squ. = AB squ. + BC squ.
AC squ. = (5) squ. +( 12) saq.
AC squ. = 25+144=169
AC =13
And we know that, circumcenter of right angled triangle is at the mid point of the hypotenuse.
so 1/2Ac= 6.5
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