Question

In ∆ ABC, angle A = 70° , angle ABD=130°. find angle ACB​

Answer 1

Answer:

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Step-by-step explanation:

Angle ABD+Angle ABC =180°..Angles in linearpair

130° + Angle ABC = 180°

Therefore,

Angle ABC = 180°-130° = 50°

Angle ABC = 50°

Angle A = Angle BAC

Therefore,

Angle BAC + Angle ACB + Angle ABC = 180°

[The sum of length of all angles of a triangle=180°]

70 + Angle ACB + 50 = 180

130 + Angle ACB = 180

Angle ACB = 180 - 130

Therefore,

Angle ACB = 50°

Answer 2

Step-by-step explanation:

Given :-

angle A = 70°

angle ABD = 130°

angle ACB = ?

Let angle C be x

We know that, Exterior angle of any triangle is equal to the sum of the two opposite interior angles.

Then,

Angle A + Angle C = Angle ABD

70° + x = 130°

x = 130° – 70°

x = 60°

THEREFORE,

ANSWER:-

Angle C = 60°

HOPE THIS HELPS!!! YOU!!