In ∆ABC, angle A = 75°, angle C = 35° and internal bisector of angle B meets AC at D. Prove that BD = CD.
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the B=70°(because the 75°+35°+B=180°)
so,DBC=35°(BD is an bisector)
now,∆CDB is an isosceles triangle because it has two same angle (35° &35°)
so,DCB angle=DBC angle
so ,CD=DB
hence,proved
so,DBC=35°(BD is an bisector)
now,∆CDB is an isosceles triangle because it has two same angle (35° &35°)
so,DCB angle=DBC angle
so ,CD=DB
hence,proved
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