Math, asked by physicalsciencemaths, 11 months ago

In ABC angle A =90 degree. If AC = 8cm, AB =6cm, then sin B? ​

Answers

Answered by paulsayantani
5

Answer:

3/5

Step-by-step explanation:

AB= 6cm

AC= 8cm

As angle A is 90°, it is a right angker triangle.

Therefore by Pythagoras theorem,

BC^2 = AB^2 + AC^2

= 6^2 + 8^2

= 36+ 64

= 100

BC = √100

=10

sin B = perpendicular÷ hypotenuse

= 6÷ 10

= 3/5

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