In ABC angle A =90 degree. If AC = 8cm, AB =6cm, then sin B?
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Answered by
5
Answer:
3/5
Step-by-step explanation:
AB= 6cm
AC= 8cm
As angle A is 90°, it is a right angker triangle.
Therefore by Pythagoras theorem,
BC^2 = AB^2 + AC^2
= 6^2 + 8^2
= 36+ 64
= 100
BC = √100
=10
sin B = perpendicular÷ hypotenuse
= 6÷ 10
= 3/5
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