In ABC, angle A = 90°, angle C = 30°, BC = 16
find AB and AC
Answers
Answered by
1
Answer:
Step-by-step explanation:
Answer:
AB=√192 BC=8
Step-by-step explanation:
sin 30=BC/AC
=>1/2=BC/16
=>BC=8cm
By pythagoras theorem,
AC^2=AB^2+BC^2
16^2=AB^2+8^2
256-64+AB^2
AB^2=256-64
AB^2=192
AB=√192cm
Answered by
0
Step-by-step explanation:
we have given a right angled triangle at A
here, BC is hypotenuse ,C=30 , B=60
AB is perpendicular to AC
sec(x)=hypotenuse/base
sec30=BC/AC
2/✓3=16/AC
=> AC=8✓3
similarly
sec 60=BC/AB
2=16/AB
AB=8
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