Question

In ABC, angle A = 90°, angle C = 30°, BC = 16
find AB and AC​

Answer 1

Answer:

Step-by-step explanation:

Answer:

AB=√192 BC=8

Step-by-step explanation:

sin 30=BC/AC

=>1/2=BC/16

=>BC=8cm

By pythagoras theorem,

AC^2=AB^2+BC^2

16^2=AB^2+8^2

256-64+AB^2

AB^2=256-64

AB^2=192

AB=√192cm

Answer 2

Step-by-step explanation:

we have given a right angled triangle at A

here, BC is hypotenuse ,C=30 , B=60

AB is perpendicular to AC

sec(x)=hypotenuse/base

sec30=BC/AC

2/✓3=16/AC

=> AC=8✓3

similarly

sec 60=BC/AB

2=16/AB

AB=8