Question

In ∆ABC , angle A + angle B = 65° and angle B + angle C=140° find the angle

Answer 1

Answer:

<A+<B+<C=180°(ASP)

(<A+<B)+<C=180

65+<C=180

<C=180-65=115°

<B+<C=140°

=<B+115=140

=<B=140-115=25°

<A+<B=65°

=<A+25=65

=<A=65-25=40°