Question

In ∆ABC , Angle A =angle B and angle C = 50° . find angle A and angle B​

Answer 1

Answer:

here we go

Step-by-step explanation:

given,

angle A= angleB

and angle C=50

angleA+angleB+angleC=180°

A+B+50=180°

IF, A=B=2A

so, 2A+50=180

2A=180-50=130

therefore:2A=130

A=130/2=65

Angle A= Angle B=65°

That's it

Hope this will be helpful

Answer 2

$\huge\bf { \red A \green N \pink S\blue W \orange E \purple R \green{...}}$

$\sf\angle A = x \: \: \: \\ \sf\angle B = x \: \: \: \\ \sf \angle C = 50°$

★ Sum of all angles in ∆ = 180°

$\longrightarrow \sf x + x + 50 = 180 \\ \\\longrightarrow \sf 2x = 180 - 50 \\ \\\longrightarrow \sf 2x = 130 \\ \\\longrightarrow \sf x = \frac{130}{2} \\ \\\longrightarrow \boxed{\sf x = 65 \degree}$

$\large \therefore \underline{ \bf \green{\angle A \: and \: \angle B = 65°}}$