Question

in ∆ABC angle A; angle B: angle C = 3:4:5.find the measure of each angle of ∆ABC​

Answer 1

Ratio of Angles of triangle :- 3 : 4 : 5

Let the first angle be :- 3x

and the second angle be :- 4x

and the third angle be :- 5x

Sum of angles of triangle :- 180°

3x + 4x + 5x = 180°

12x = 180°

x = 180°/12

x = 15°

First angle :- 3x = 3 × 15 = 45°

Second angle :- 4x = 4 × 15 = 60°

Third angle :- 5x = 5 × 15 = 75°

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Answer 2

Step-by-step explanation:

Given : In ️ ABC the ratios of angles are 3:4:5

Let angle A be 3x

angle B be 4x

and angle C be 5x

Then,

Sum of all angles of a triangle = 180°

3x + 4x + 5x = 180°

12x = 180°

x = 180° /12

x = 15

So,

angle A = 3x = 3 × 15 = 45

angle B = 4x = 4 × 15 = 60

angle C = 5x = 5 × 15 = 75