In ∆ABC, Angle A is double than angle B but angle C is 5 less than angle A. (Take y to be angle B
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Answered by
5
Answer:
angle A = 74°
angle B = 37°
angle C = 69°
Step-by-step explanation:
sum of all angles of triangle is 180°
let the angles be A, B, C
let angle B = y
angle A is double of angle B = 2y
angle C is 5 less than angle A = 2y - 5
A + B + C = 180
2y + y + 2y - 5 = 180
5y - 5 = 180
5y = 180 + 5
5y = 185
y = 185/5
y = 37
angle A = 2y = 2 × 37 = 74°
angle B = y = 37°
angle C = 2y - 5 = 2(37) - 5 = 74 - 5 = 69°
hope you get your answer
Answered by
1
Step-by-step explanation:
In triangle ghufhkvkjgjhcddhbbvdgjjffjgcvjj
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