Math, asked by kate4401, 11 months ago

In ∆ABC, Angle A is double than angle B but angle C is 5 less than angle A. (Take y to be angle B

Answers

Answered by kartik2507
5

Answer:

angle A = 74°

angle B = 37°

angle C = 69°

Step-by-step explanation:

sum of all angles of triangle is 180°

let the angles be A, B, C

let angle B = y

angle A is double of angle B = 2y

angle C is 5 less than angle A = 2y - 5

A + B + C = 180

2y + y + 2y - 5 = 180

5y - 5 = 180

5y = 180 + 5

5y = 185

y = 185/5

y = 37

angle A = 2y = 2 × 37 = 74°

angle B = y = 37°

angle C = 2y - 5 = 2(37) - 5 = 74 - 5 = 69°

hope you get your answer

Answered by snehabhsrti866
1

Step-by-step explanation:

In triangle ghufhkvkjgjhcddhbbvdgjjffjgcvjj

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