In ∆ABC,Angle ABC=150°,AD perpendicular BC,AB=20cm. Find height of∆ ABC.
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Height of the triangle is 12cm.
150/20=90/X
X=90×20/150
X=12
Hope this easy method helps
150/20=90/X
X=90×20/150
X=12
Hope this easy method helps
MASTERJEEVAN:
Hi
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