Question

in ∆ABC angle ABC = 45° angle ACD = 130° B_C_D find angle bac

Answer 1

50 Deg because it will be linear pair

or you can also use ext. angle property.

thanks

Answer 2

Given: In Triangle ABC  Angle ABC= 45° Angle BCD= 130° Angle BAC= ?  Solution: Sum Of Measures Of All Angles Of A Triangle Is 180° Therefore, Angle ABC+ Angle BCD+ Angle BAC=  180° 45 + 130 + Angle BAC = 180° 175 + Angle BAC = 180° Angle ABC = 180°-175°                     = 5° Therefore, Angle BAC = 5°  Hope it Helps