In ∆ABC ,Angle ABC= 90° Seg CD
perpendicular to Side AB and Seg CE is an angle bisector of Angle ACB.
Prove that : AD/BD =AE<2/BE<2
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only interchange the letters if you got it right let me know
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HIT007:
can you tell me the name of the above book??
Master Key Pg152
which standard?? 10th or 12th??
and which board??
10 ssc
ok
Thanks
did u get it right for todays paper
I used the other method but i think that method is wrong
ok
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