In ∆ABC, angle ABC= angle ACB. If the side BC is produced both ways. Prove that the exterior angles are equal.
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GIVEN: ∠ABC = ∠ACB
Line BC has produced both ways
TO PROVE: Exterior Angles are equal.
∠ABD = ∠ACE
SOLUTION:
In the figure,
∠ABD + ∠ABC = 180° (Linear Pair)
∠ABD = 180° - ∠ABC -------- Eq 1
Similarly,
∠ACB + ∠ACE = 180° (Linear Pair)
∠ACE = 180° - ∠ACB -------- Eq 2
Now,
Taking Eq 1,
∠ABD = 180° - ∠ABC
∠ABD = 180° - ∠ACB ---- Eq 3 (Since, ∠ACB = ∠ABC )(Given)
Solving Eq 2 and Eq 3,
We get,
∠ABD = ∠ACE
Hence Proved.
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