Question

in ∆abc angle b = 90, ab=bc, ac=4√2 find the perimeter of ∆ABC ​

Answer 1

Answer:

8+4√2

Step-by-step explanation:

let ab be x ,then bc will also be x (ab=bc,given)

by PT

(ab)²+(bc)²=(ac)²

(x)²+(x)²=(4√2)²

x²+x²=32

2x²=32

x²=32/2

x²=16

x=√16

x=4

ab=bc=4

perimeter=ab+bc+ca

=4+4+4√2

=8+4√2