In ABC, angle B =90°, AD =DC, AB = BC and AB = 12 cm.
Then find the area of AABD.
Answers
Answered by
2
Step-by-step explanation:
area of triangle =1/2*base*height
= 1/2*bc*ab
=1/2*12*12
=1/2*144
=72cm square
Answered by
0
Answer:
if AB=BC then the triangle ABC is a right angled isosceles triangle.
ATQ:
1/2*12*12
=6*12
=72 square cm
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