Math, asked by gaddelatha, 1 year ago

In ABC, angle B =90°, AD =DC, AB = BC and AB = 12 cm.
Then find the area of AABD.​

Answers

Answered by smaanunavypolice
2

Step-by-step explanation:

area of triangle =1/2*base*height

= 1/2*bc*ab

=1/2*12*12

=1/2*144

=72cm square

Answered by aditi2247
0

Answer:

if AB=BC then the triangle ABC is a right angled isosceles triangle.

ATQ:

1/2*12*12

=6*12

=72 square cm

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