in ∆ ABC angle B=90° , angle A=45° ,AB=5cm ,Ac=?
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Step-by-step explanation:
In Triangle ABC, ∠B = 90° , ∠A = 45° -----> given
therefore ∠C = 45° ------> ( remaining angle of a triangle )
Therefore triangle ABC is a 45°-45°-90° triangle
therefore by 45°-45°-90° triangle theorem ,
side opposite to 45° = 1/√2 * hypotenuse
AB = 1 / √2 * AC
5 = 1 / √2 * AC
5 * √2 = AC
Therefore AC = 5√2 cm
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