Question

in ∆ ABC angle B=90° , angle A=45° ,AB=5cm ,Ac=?​

Answer 1

Step-by-step explanation:

In Triangle ABC, ∠B = 90° , ∠A = 45° -----> given

therefore ∠C = 45° ------> ( remaining angle of a triangle )

Therefore triangle ABC is a 45°-45°-90° triangle

therefore by 45°-45°-90° triangle theorem ,

side opposite to 45° = 1/√2 * hypotenuse

                            AB = 1 / √2 * AC

                              5 = 1 / √2 * AC

                             5 * √2 = AC

Therefore AC = 5√2 cm