In ∆ABC, angle B=90° seg BD is perpendicular to hypotenuse AC, BE is angle bisector of angle ABC then prove that AD/DC =AE²/EC²
Answers
Answered by
1
Answer:
Excuse me buddy please check your question .
Explanation: According to question , seg BD is perpendicular to hypotenuse AC, BE is angle bisector of angle ABC , there is no chance to solve the question furtherly .
Because if BD ⊥ AC , then BD is the only bisector of ∠ABC , there is no involvement of BE .
OK.
So, please check your question the ask it to me .
If you like my above error finding please mark it as brainliest , because I m only 1 brainliest before VIRTUOSO .
Similar questions