Question

In ∆ ABC angle B = 90° seg BD is the median,
If AB = 3, BC = 4, then (BD) =?​

Answer 1

Answer:

AC² = AB² + BC²

AC² = (3)² + (4)²

AC² = 9 + 16

AC² = 25

AC = √25

AC = 5

In △ABC,

∠B = 90°, AB = 3, BC = 4,AC = 5

$SinC = \frac{AB}{ AC} \: = \: \frac{3}{5} \: \: \: → \: 1$

In △BDC

∠BDC = 90°, BC = 4

$SinC = \frac{BD}{ BC} \: \: \: \: → \: 2$

Comparing 1 and 2

$\frac{3}{5} \: = \: \frac{BD}{4} \: → \: BD \: = 3.4$