Math, asked by Deepjyoti11, 1 year ago

In ∆ABC, angle B = 90°and tanA = 1, then show that the 2sinA. cosA=1

Answers

Answered by HridayAg0102
44
Heya Frnd.........☺

Since TanA = 1

So,

A = 45° ..........(Tan45 = 1)

NOW,

2 \sin(a) \times \cos(a)

 = > \: 2 \sin(45) \times \cos(45)

 = > \: 2 \: (\frac{1}{ \sqrt{2} } ) \times \frac{1}{ \sqrt{2} }

 = > \: 2( \frac{1}{2} )

 = > \: 1 \: ............hence \: proved

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Answered by Keshavkr1
18
look at the picture....
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