Question

In ∆ABC, angle b=angle c ,prove ac line segment=ab line segment​

Answer 1

Answer:

In Triangle ABC we have :-

∠B = ∠C

AC = AB ( sides opposite to equal angles are equal )

AE + EC = AD + DB

AE + CE = AD + BD

AE + CE = AD + CE ( BD = CE)

AE = AD

Thus we are having :-

AD = AE and BD = CE

Therefore, AD/BD = AE/CE

AD/DB = AE/EC

DE // BC ( By converse of Thales Theorem )

\huge{\boxed{\sf{HENCE\:PROVED!}}}

Answer 2

Answer:

DE || BC

Step-by-step explanation:

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