In Δ ABC, angle BAC = 90°, AD┴BC BD = 4cm, CD = 5cm find x and y
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Step-by-step explanation:
let AB = x, BD = y, and BC = z
from triangle ABC
x2 + z2 =(4+5)2=81 --------(1)
from triangle ADB
x2= y2+16 ------------(2)
from triangle BDC
z2= y2 + 25 ----------(3)
substituting (2) and (3) in (1)
(y2+16)+(y2+25)=81
y2 =20------------(4)
y=2 root 5
substituting (4) in 2
x2= 20+ 16
x=6
thus BD = 2 root 5
AB=6
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