In Δ ABC, angle BAC= 90°, AD is the altitude if AB = 2√5, BD = 4. Then find BC and AC
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Answer:
AB
2
=BC.BD [using the corollary]
(2
5
)
2
=BC×4
∴
4
20
=BC
∴BC=5
Now, CD=BC−BD=5−4=1
AC
2
=BC.CD
⟹AC
2
=5×1
∴AC=
5
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