Question

in ∆abc ,angle c=90.if bc = a,ca=b,ab=c and perpendicular drawn from c on ab having height p then prove cp= ab and 1/p^2=1/a^2+1/b^2​

Answer 1

ar of ∆abc=1/2× b×h
=1/2×ab×cd
=1/2×c×p-(1)
ar of ∆abc =1/2×bc× Ac
=1/2× a×b
1/2ab-(2)
from (1)and (2)
cp=ab
¡¡)cp=ab
c=ab/p

in ∆abc
by Python
ab^=ac^+bc^
c^=b^+ a^
(ab/p)^=b^+ a^/1
a^b^/p^=b^+a^/1
1/p^= b^+a^/a^b^
1/p^=b^/a^b^+a^/a^b^
=1/p^=1/a^+1/b^

Answer 2

Answer:

true

Step-by-step explanation:

yes it is true using the thales theorem