in ∆ABC,angleA=35°,anlgeB=80°
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angle c+a+b =180
c+35+80=180
c+115=180
c=180-115
c=65
c+35+80=180
c+115=180
c=180-115
c=65
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If Angle
A=35°
B=80°
Then angle C will be....
Angle A+B+C=180° [Angle sum property of a triangle]
=35°+80°+C=180°
=115°+C=180°
=C=180°-115°
Therefore, Angle C=65°
A=35°
B=80°
Then angle C will be....
Angle A+B+C=180° [Angle sum property of a triangle]
=35°+80°+C=180°
=115°+C=180°
=C=180°-115°
Therefore, Angle C=65°
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