In ∆ABC, angleA=angleB + angleC. angleA = 90°. If it further given that angleB = 2angleC, find angleB and angleC.
please tell me fast tomorrow is my test.
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Answer:
Let angle B be x
and angle C = 2x
angle A = 90° (given)
ATP,
angleA + angle B + angle C = 180° (A.S.P)
=) 90° + x+ 2x = 180°
=) 90° + 3x = 180°
=) 3x = (180 - 90)°
=) 3x = 90
=) x = 90/3
=) x = 30 .
therefore, angle B = 30° and angle C = (30×2)° = 60° . (Answer )
and , angle A =90° = angle B + angle C = (60+30)° = 90° . Hence Proved .
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