Question

In ∆ABC , angleACB = 90. Seg CD is perpendicular to seg AB
and seg DE is perpendicular to seg CB
show that CD² x AC = AD × AB ×DE.​

Answer 1

REFER TO THE ATTACHMENT

FOR SOLUTION

The theorem used is stated as

If perpendicular is drawn from 90 degree vertex of right triangle on the hypotenuse then the triangles on both sides of hypotenuse are similar.