In ∆ABC , AngleB = 90 if CosA= 4/5 then find
1.length of BC.
2.Tan A.
3.Sin A
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Answer:
tan A
Step-by-step explanation:
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SinA*sinA=1-cosA*cosA=1-(16/25)=9/25
SinA=3/5
1.length of BC=3(opposite of angle A)
2.tanA=3/4(SinA/cosA)
3.SinA=3/5
SinA=3/5
1.length of BC=3(opposite of angle A)
2.tanA=3/4(SinA/cosA)
3.SinA=3/5
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