In ∆ABC, angleB = 90°, angle c = 60° ,angle A = 30°, AC=16, find
BC and AB
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Answer:
AB=√192 BC=8
Step-by-step explanation:
sin 30=BC/AC
=>1/2=BC/16
=>BC=8cm
By pythagoras theorem,
AC^2=AB^2+BC^2
16^2=AB^2+8^2
256=64+AB^2
AB^2=256-64
AB^2=192
AB=√192cm
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