In ∆ABC, angleB = angleC and AD perpendicular to BC. Prove that ∆ABD congruent to ∆ACD.
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Step-by-step explanation:
in triangle ABD and triangle ACD
angle abd = angle acd (given)
side ad = side ad. (common)
AD is perpendicular so
angle adb = angle adc (90°)
by RHS congruency
triangle ABD is congruent to triangle ACD
Answered by
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Answer:
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