Question

In ∆ABC.,angleC=90° if tan=1/√3. find CosB+SinB CosA by using table. please ans fast

Answer 1

Let take ∅ angle as B then
tanB = 1/√3
tanB = perpendicular/base
so AC = 1. and BC = √3

using Pythagoras thereom
AB² = AC²+BC²
AB² = 1²+√3²
AB² = 1+3
AB = √4
AB = 2

cosB = base/tangent
cosB = √3/2

sinB = perpendicular/base
sinB = 1/2

let take∅ angle as A
cosA = base/tangent
cosA = 1/2

cosB+sinB×cosB
=√3/2+(1/2×1/2)
=√3/2+1/4
=2√3+1/4