Question

in Δ ABC,AP corresponding BC ,BQ corresponding AC,B-D-C,A-Q- to prove ΔCQAparallel ΔCQB , complete the following activity
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Answer 1

ANSWER

REF. Image.

Given AB=AC

and AP=AQ

Thus

AB-AP=AC-AQ

[BP=CA ]      [from figure ]

now InΔBCP & ΔBCQ

BP = CQ

∠c=∠c  [common]

and BC=BC  [common]

∴ΔBCP≃ΔBCQ  [SAS congruency]

now

[BQ=CP] [corresponding parts of congruent triangles]

solution