Question

In ∆ABC, AP, I BC, BO I AC
B-P-C, A-Q-C then prove that,
∆ CPA - ∆CQB.
If AP = 7, BQ=8, BC=12
then find AC.​

Answer 1

Step-by-step explanation:

In ∆CPA & ∆CQB,

angle P= angle Q----(each 90°)

angle PCA= angle QCB------( common angle)

Therefore ∆CPA~∆CQB--(By AA test)

cp/cq=pa/qb=ca/CB------(c.s.s.t)

pa/qb=ca/cb

7/8=ca/12

ca=7×12/8

ca=10.5