Question

In ∆ABC, AP perpendicular BC, BQ perpendicular AC, B-P-C and A-Q-C, then Write the proportionality of the corresponding sides of ∆CPA and ∆CQB.​

Answer 1

Answer:

Step-by-step explanation:

Step-by-step explanation:

In ΔCPA and ΔCQB

AP⊥BCGIVEN

BQ⊥ACGIVEN

∠CPA=90°1

∠CQB=90°.2

∠CPA≅∠CQB.from 1 and 2

∴ΔCPA~ΔCQB

In ΔABC

AP=7

BQ=8

BC=12

AC=?

∴AP/BQ=AC/BC

∴7/8=AC/12

∴AC= 12 x 7/8

∴AC=10.5

Answer 2

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