Math, asked by Anonymous, 4 months ago

In Δ ABC ∠B = 2 ∠C and bisector of ∠B intersect AC at D . Prove that BD / DA = BC / BA.

Answers

Answered by tappukhan2010

0

In ∆ ABC , BD is bisector ∠B

CD/AD =BC/BA

BD/AD = BC/BA

→ BD/DA = BC/ BA

Hence proved

Answered by tejasvinisinhaps23

1

hence it is proved

darling mark me brainliest

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