In ∆ABC, ∠B = 45°, ∠C = 55° and the bisector of ∠A meets BC at point D. Then ∠ADB will be
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Answer:
Hope my answer helps you mate :-)
Step-by-step explanation:
In Triangle ABC
By angle sum property
A+B+C=180
A+55+45=180
A=80 degree
Now in Triangle ADB
Angle BAD=40 as AD is bisector of angle A
Now in triangle BAD by angle sum property of triangle
BAD+B+ADB=180
40+45+ADB=180
ADB=180-85=95
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Solve it by angle sum property
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