Question

In ∆ABC, \B=60⁰,/C=40⁰,AD is the bisector of/A and AE is drawn perpendicular on BC from A. Then the measure of /EAD is​

Answer 1

Step-by-step explanation:

Given :

∠B = 60°

∠C = 40°

As we know that

∠A + ∠B + ∠C = 180°

∠A = 180° - 60° - 40°

∠A = 80°

∴ ∠BAD = 80∘2

= 40°

In ΔAEB

∠A + ∠B + ∠E = 180°

∠A = 180° - 60° - 90°

∠A = 30°

Then,

∠DAE = ∠DAB - ∠EAB

∠DAE = 40° - 30°

∠DAE = 10°

By Trick

∠DAE=∠B−∠C2=60∘−40∘2=10∘