Question

In ABC, B =60 C =40 Al perpendecular BC and AD bisects A such that L and D lie on side BC Find LAD​

Answer 1

Answer:

Step-by-step explanation:

Angle B = 260 and angle C equals to 40 degree in triangle abc equal to angle 16 degree + 40 degree + angle equals to 180 degree angle equals to 180 degree - 100 degree equals to 18 degree it is the bisector of the angle so angle C is equal to angle dmp no angle C is equals to 18.2 equals to 40 degree now in triangle AC and equals to 19 + 40 degree + angle C is equals to 180 degree angle C A L = to 180 degree minus 30 degree equals to 50 degree angle LED equals to angle C A T - angle C A L = 250 degree minus 40 degree equal to 10 degree so angle and is equals to 10 degrees

Answer 2

We know that the sum of all angles of a triangle is 180°.

Consider △ABC,

we can write as ∠A + ∠B + ∠C = 180°.

∠A + 60° + 40° = 180°

∠A = 80°

But we know that,

∠DAC bisects ∠A

∠DAC = ∠A/2

∠DAC = 80°/2 .

If we apply same steps for the △ADC, we get,

We know that the sum of all angles of a triangle is 180°.

∠ADC + ∠DCA + ∠DAC = 180°

∠ADC + 40° + 40° = 180°

∠ADC = 180° + 80° .

We know that exterior angle is equal to the sum of two interior opposite angles .

Therefore we have,

∠ADC = ∠ALD + ∠LAD

But here,

AL perpendicular to BC

100° = 90° + ∠LAD

∠LAD = 90°.......... answer..