In ∆ ABC, ∠B= 76°
, ∠C= 64° and D is a point on BC, such that AD is
bisector of ∠A, Find ∠ADC.
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Answer:
∠ADC = 96°
Step-by-step explanation:
in triangle ABC angle A is biaect so ABC = 180°
180°- 76+64
40°
angle ADC = 180 - 64+20 = angle ADC = 96°
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