In ∆abc, /_ b=90, ab=(2x+1) cm and bc=(x+1) cm. If the area of the ∆abc is 60 cm^ 2 find its perimeter
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area of triangle is equal to one upon two length into breadth and area of triangle is equal to one upon two 2 X + 1 into X + 1 is equal to 1 upon 2 X square + 3 X + 1
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