In ∆ ABC, ∠B = 90 ,∠C = 60 , if AC = 8 find AB. *
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AB=6cm
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Answer:
use Pythagoras' theorem
abc = right angled triangle
ca = hypotenuse
so ac square = ab square + bc square
angle c = 60
angle a = 30
so c square is bigger than a square
ab + bc squared = ca squared =8*8 =64
ab squared + bc squared = 64
bc is bigger
so only combination possible =37 + 27 = 37 square rooted n 27 square rooted
ab=5.196
bc=6.083
hope it helps mate
brainliest plzzzzz
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