Question

. In ∆ ABC, ∠B = 90°, ∠A = 30°,∠C = 60° , AC = 14 , then find AB and BC​

Answer 1

In ∆ ABC,

angle B-90°,A-30°,C-60°

by 30°-60°-90°(theorem)

BC-1/2×AC

BC-1/2×14

BC-7

AB-√3/2×AC

√3/2×14

7√3

Answer 2

Answer:

The values of  AB and BC $12.12,7$ respectively

Step-by-step explanation:

Given:

Angle B is $90^0$

Angle A is $30^0$

Angle C is $60^0$

$AC=14$

We need to find the values of  AB and BC

By applying sine rule we get the condition as

$\frac{AB}{sin60^0} =\frac{BC}{sin30^0} =\frac{14}{sin90^0}$

$\frac{AB}{sin60^0} =\frac{14}{sin90^0} \\\\AB=14*\frac{\sqrt{3} }{2} \\\\AB=12.12$

$\frac{BC}{sin30^0} =\frac{14}{sin90^0} \\\\BC=14*\frac{1}{2}\\\\BC=7$