In Δ ABC,∠B=90°, A-D-C, AD=DC, BD⊥AC, BD=5, AB=8, then BC = ?
(Answer with full explanation)
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Answered by
1
Answer:
3.4
Step-by-step explanation:
△ABC is right angled △,∠B=90°
BD⊥AC
AB=3,AC=5
By Pythagoras theorem,
AB
2
+BC
2
=AC
2
⇒BC
2
=AC
2
−AB
2
=5
2
−3
2
⇒BC=4
In △ABC,
∠B=90°,AB=3,BC=4,AC=5
sinC=
AC
AB
=
5
3
→1
In △BDC
∠BDC=90°,BC=4
sinC=
BC
BD
→2
Comparing 1 and 2
5
3
=
4
BD
⇒BD=3.4
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Answered by
0
Answer:
3.4
Step-by-step explanation:
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