Question

In ∆ ABC, B= 90°,AB = 5 units, BC = 2 units.

Find the area of ∆ ABC.​

Answer 1

Answer:

5 units

Step-by-step explanation:

Area of triangle is = 1/2*b*h

=1/2*2*5

=5 units

Answer 2

$\huge \bold \color{green}{ \underline{ \underline \red{required \: answer : }}}$

$\huge \bold { \underline{ \underline{given : }}}$

angle B = 90°

AB = 5 units

BC = 2 units

$\bold{if \angle \: b = 90 \degree }\\ \bold{so \: the \: \triangle \: is \: a \: right \:angled \: triangle}$

in which AB is perpendicular and BC is base..

so area of triangle =

$\bold{\frac{1}{2} \times base \times height}$

$\bold{ar \triangle = \frac{1}{2} \times 2 \times 5} \\ \bold{ar \triangle = 5 {units}^{2} }$

so area of triangle is 5 square units..