Question

InΔABC,∠B=90°,segBD⟂sideAC.IfDC=10cm,BD=20cm.Find AD.​

Answer 1

Answer:

Let ABC be a triangle with angle A = 90 degrees and AB = AC. ... Then,as we know that from theorem of ∆ ABC,if <B=90° and BD perp. to AC is BD²=AD.CD ... If AP^2=BP^2+CP^2, how do you find angle BPC?

Answer 2

Answer:

AB-AC

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