In ΔABC, ∠B = 90o
, AB = 6 cm and AC = 12 cm. Find ∠A and ∠C.
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Answer:
we know that ABC is the right angle triangle,
so,
AC×AC= AB×AB×BC×BC
12×12=6×6×BC×BC
144=36×BC×BC
BC×BC=144÷36
BC×BC=4
BC=2
Now,
We know that,
angle A+angel B+angel C=180°
angle A+90°+angle C= 180
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